# Today I Learned

## Sum of Squares and Torque

Suppose we have the mass of each dot on the coordinate system as $m$, the overall torque due to gravity is

This can be generalized to arbitary $n$,

On the other hand the total torque of the system is simply the displacement of center of gravity cross total gravitational force.

The center of the gravity is at $2/3$ on the line that is perpendicular to the base of the isosceles triangle, which is

where the $1$ is because the top of the triangle is at coordinate 1.

The value of total gravitational force is the sum is

Now the torque due to gravity is

The two views should give us the same result, which means

By OctoMiao

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